Power of a Power Property of Exponents
Adding and Subtracting Rational Numbers
Solving Equations with Radicals and Exponents
Quadratic Equations
Using Intercepts for Graphing Linear Equations
Graphing Linear Equations in Two
Multiplying Fractions
Solving Linear Equations Containing Fractions
Evaluating Polynomials
Multiplication Property of Square and Cube  Roots
Writing a Fraction in Simplest Form
Square Roots
The Pythagorean Theorem
Factoring The Difference of 2 Squares
Solving Polynomial Equations
Roots and Powers
Writing Linear Equations in Standard Form
Solving Nonlinear Equations by Substitution
Straight Lines
The Square of a Binomial
Solving Equations
Adding and Subtracting Like Fractions
Finding the Equation of an Inverse Function
Slope of a Line
Rules for Nonnegative Integral Exponents

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Point-Slope Form for the Equation of a Line


Find the equation of the line that passes through the points (-2, 7) and (6, 3). Write your answer in point-slope form.


To find the equation in point-slope form, we first find m, the slope of the line.

Let (x1, y1) = (-2, 7) and (x2, y2) = (6, 3). m
Substitute the values in the slope formula.  
The slope of the line is .

Now that we have the slope and a point, we can use the point-slope form to find the equation of the line.

 y - y1 = m(x - x1)
Substitute for m.

We can substitute either given point for (x1, y1). Let’s use (6, 3).

y - y1
Therefore, substitute 6 for x1 and 3 for y1. y - 3

The point-slope form of the equation of the line that passes through (-2, 7) and (6, 3) is


If we had used the other point, (-2, 7), we would have obtained:

This equation is equivalent to